TITLE: Creating a derived class creates a new scope level

[ This material adapted from "C++ Gotchas", tutorial notes by
  Tom Cargill, p. 13]

	#include <stdio.h>

	class B {
	  public:
	    void foo (double d) { printf ("B::foo(%g)\n", d); }
	};

	class D : public B {
	  public:
	    void foo (int i) { printf ("D::foo(%d)\n", i); }
	};

	int main ()
	{
	    D d;
	    d.foo (1.5);
	    return 0;
	}

Results in the following output:

	D::foo (1)

If a client in main wanted to call the inherited version of foo,
it could be done with the line

	d.B::foo (1.5);

Aside -
    Note that foo is NOT virtual. If it had been virtual, the compiler
    would have warned about hiding the inherited version of foo. Keep
    in mind that it is usually a BAD idea to have a derived class with
    a member of the same name as the base class, where that member
    is NOT virtual.